Let
s
≡ 1 + α+ α
2
+ α
3
+ α
4
+ …,
α
s
= α+ α
2
+ α
3
+ α
4
+ …,
Hence,
(1 − α)
s
= 1,
and
s
=
1
1− α
.
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On 13 Jun 2022, 12:41.